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X^2+29X+195.99=0
a = 1; b = 29; c = +195.99;
Δ = b2-4ac
Δ = 292-4·1·195.99
Δ = 57.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{57.04}}{2*1}=\frac{-29-\sqrt{57.04}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{57.04}}{2*1}=\frac{-29+\sqrt{57.04}}{2} $
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